航空百大

標題:

Silmiar Triangle

發問:

https://i.na.cx/fNCkV8.png 主要唔識 II / III

最佳解答:

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24. The answer is : D. I and III only I. must be correct AB = CD (given) ∠CAB = ∠ECD(given) ∠ABC = ∠CDE(given) ΔABC ? ΔCDE (ASA) III. must be correct From I, ΔABC ? ΔCDE (proven) CA = CE (corr. sides, cong. Δs) Hence, ΔEAC must be an isos. Δ. II. may be incorrect From III, ΔEAC is an isos. Δ. It CANNOT prove that ΔABC is an isos. Δ. Hence, ΔABC may NOT be similar to ΔEAC.

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