標題:
What is the reaction between F2(II)SO4 and K2Cr2O7?
發問:
What is the reaction between Fe(II)SO4 and K2Cr2O7? Is Fe(II)SO4 oxidized? Please give the equation! 更新: Can you make your equations that better to my understanding? Are they balanced? Can you give me full equation? Your effort is appreciated!!!
Fe(II) is oxidized to Fe(III) Fe(II) -->Fe(III) ＋ e Cr2O7^2- is reduced to Cr3＋ Cr2O7^2- ＋ 14H＋ ＋ 6e --->2Cr3＋ ＋ 7H2O The equation is: 6Fe(II) ＋ Cr2O7^2- ＋ 14H＋ --->6Fe(III) ＋ 2Cr3＋ ＋ 7H2O The solution is changed from greenish orange to greenish yellow 2007-10-14 18:05:27 補充： The full equation is 6Fe(II) ＋ Cr2O7^2- ＋ 14H＋ --->6Fe(III) ＋ 2Cr3＋ ＋ 7H2OThey are all balanced 2007-10-14 18:05:48 補充： Fe(II) ------------------------------->Fe(III) ＋ e-----------X6＋) Cr2O7^2- ＋ 14H＋ ＋ 6e --->2Cr3＋ ＋ 7H2O--X1_____________________________________________6Fe(II) ＋ Cr2O7^2- ＋ 14H＋ --->6Fe(III) ＋ 2Cr3＋ ＋ 7H2O
其他解答:
What is the reaction between F2(II)SO4 and K2Cr2O7?
發問:
What is the reaction between Fe(II)SO4 and K2Cr2O7? Is Fe(II)SO4 oxidized? Please give the equation! 更新: Can you make your equations that better to my understanding? Are they balanced? Can you give me full equation? Your effort is appreciated!!!
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最佳解答:Fe(II) is oxidized to Fe(III) Fe(II) -->Fe(III) ＋ e Cr2O7^2- is reduced to Cr3＋ Cr2O7^2- ＋ 14H＋ ＋ 6e --->2Cr3＋ ＋ 7H2O The equation is: 6Fe(II) ＋ Cr2O7^2- ＋ 14H＋ --->6Fe(III) ＋ 2Cr3＋ ＋ 7H2O The solution is changed from greenish orange to greenish yellow 2007-10-14 18:05:27 補充： The full equation is 6Fe(II) ＋ Cr2O7^2- ＋ 14H＋ --->6Fe(III) ＋ 2Cr3＋ ＋ 7H2OThey are all balanced 2007-10-14 18:05:48 補充： Fe(II) ------------------------------->Fe(III) ＋ e-----------X6＋) Cr2O7^2- ＋ 14H＋ ＋ 6e --->2Cr3＋ ＋ 7H2O--X1_____________________________________________6Fe(II) ＋ Cr2O7^2- ＋ 14H＋ --->6Fe(III) ＋ 2Cr3＋ ＋ 7H2O
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